"aaltonen" <harri.aaltonen@mail.vak.fi> wrote in message news:1172089463.908676.22057 0@v33g2000cwv.googlegroups.com... > What is the area of the largest isosceles right triangle you can fit > inside a unit cube? Harri, it's hard to feel completely sure, but shaking the triangle in the box, wouldn't it put a small side on the floor, 45 angle in a corner, 90 angle on a floor edge, and lean against the far wall, 1 up? That makes the small side 1.13224 ... and the area of the triangle 1/2+2/(1+SQRT(2)+SQRT(2*SQRT(2)-1))^2 = 0.64099 ... Any better way? Hans.